A 15 , m long bamboo leans on a wall to reach | vedclass

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(D) Let the length of the bamboo be the hypotenuse $c = 15 \, m$.Let the height reached on the wall be one leg $a = 12 \, m$.Let the distance from the

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(D) Let the length of the bamboo be the hypotenuse $c = 15 \, m$.Let the height reached on the wall be one leg $a = 12 \, m$.Let the distance from the base of the wall be the other leg $b$.According to the Pythagorean theorem,$a^2 + b^2 = c^2$.Substituting the values,we get $(12)^2 + b^2 = (15)^2$.$144 + b^2 = 225$.$b^2 = 225 - 144 = 81$.$b = \sqrt{81} = 9 \, m$.Thus,the lower end of the bamboo is $9 \, m$ away from the base of the wall.

$A$ $15 \, m$ long bamboo leans on a wall to reach the height of $12 \, m$ on the wall. Then,the lower end of the bamboo is $\ldots \ldots \, m$ away from the base of the wall.

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