A 124 W bulb converts only 15 % of the ener | vedclass

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(B) The power supplied is $P = 124 \ W = 124 \ J/s$.The energy converted into visible light per second is $E_{	ext{light}} = 124 	imes 0.15 = 18.6 \

Vedclass · Accepted Answer

$6 	imes 10^{19}$

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(B) The power supplied is $P = 124 \ W = 124 \ J/s$.The energy converted into visible light per second is $E_{	ext{light}} = 124 	imes 0.15 = 18.6 \ J$.The energy of one photon is $E = \frac{hc}{\lambda} = \frac{1240 \ eV \cdot nm}{640 \ nm} = 1.9375 \ eV$.Converting energy of one photon to Joules: $E = 1.9375 	imes 1.602 	imes 10^{-19} \ J \approx 3.1 	imes 10^{-19} \ J$.The number of photons emitted per second is $n = \frac{E_{	ext{light}}}{E} = \frac{18.6}{3.1 	imes 10^{-19}} = 6 	imes 10^{19}$ photons.

$A$ $124 \ W$ bulb converts only $15 \ \%$ of the energy supplied to it into visible light of wavelength $640 \ \text{nm}$. How many photons are emitted by the light bulb in one second?

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