A bag contains 5 black and 6 red balls. Deter | vedclass

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(A) There are $5$ black and $6$ red balls in the bag.$2$ black balls can be selected out of $5$ black balls in $^{5}C_{2}$ ways.$3$ red balls can be s

Vedclass · Accepted Answer

$200$

Vedclass · Answer

(A) There are $5$ black and $6$ red balls in the bag.$2$ black balls can be selected out of $5$ black balls in $^{5}C_{2}$ ways.$3$ red balls can be selected out of $6$ red balls in $^{6}C_{3}$ ways.Thus,by the multiplication principle,the required number of ways of selecting $2$ black and $3$ red balls is:$= ^{5}C_{2} 	imes ^{6}C_{3} = \frac{5!}{2!3!} 	imes \frac{6!}{3!3!} = \frac{5 	imes 4}{2 	imes 1} 	imes \frac{6 	imes 5 	imes 4}{3 	imes 2 	imes 1} = 10 	imes 20 = 200$.

$A$ bag contains $5$ black and $6$ red balls. Determine the number of ways in which $2$ black and $3$ red balls can be selected.

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