A bag contains 3 white,3 black,and 2 red ball | vedclass

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(D) The total number of balls is $3 + 3 + 2 = 8$.Since we are drawing three balls one by one without replacement,the probability that the $k$-th ball

Vedclass · Accepted Answer

$\frac{1}{4}$

Vedclass · Answer

(D) The total number of balls is $3 + 3 + 2 = 8$.Since we are drawing three balls one by one without replacement,the probability that the $k$-th ball is of a certain color is equal to the initial proportion of that color in the bag.Let $R_3$ be the event that the third ball drawn is red.By the principle of symmetry in sampling without replacement,the probability of any specific draw being a certain color is the same as the probability of the first draw being that color.Therefore,$P(R_3) = P(R_1) = \frac{	ext{Number of red balls}}{	ext{Total number of balls}} = \frac{2}{8} = \frac{1}{4}$.

$A$ bag contains $3$ white,$3$ black,and $2$ red balls. Three balls are drawn one by one without replacement. The probability that the third ball is red is:

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