A bag contains 3 red and 7 black balls. Two b | vedclass

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(D) Total number of red balls $= 3$.Total number of black balls $= 7$.Total number of balls $= 3 + 7 = 10$.We are given that the first ball drawn is r

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$\frac{2}{9}$

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(D) Total number of red balls $= 3$.Total number of black balls $= 7$.Total number of balls $= 3 + 7 = 10$.We are given that the first ball drawn is red.Since the balls are drawn without replacement,after drawing one red ball,the number of remaining red balls $= 3 - 1 = 2$.The total number of remaining balls $= 10 - 1 = 9$.The probability that the second ball is red,given that the first ball was red,is the ratio of the number of remaining red balls to the total number of remaining balls.Required probability $= \frac{2}{9}$.

$A$ bag contains $3$ red and $7$ black balls. Two balls are taken out at random,without replacement. If the first ball is red,what is the probability that the second ball is also red?

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