A bag contains 7 black and 5 white balls. A b | vedclass

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(B) Total number of balls $= 7 + 5 = 12$.Probability of drawing a white ball in the first draw $P(W_1) = \frac{5}{12}$.Since the ball is replaced,the

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$\frac{25}{144}$

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(B) Total number of balls $= 7 + 5 = 12$.Probability of drawing a white ball in the first draw $P(W_1) = \frac{5}{12}$.Since the ball is replaced,the total number of balls remains $12$ and the number of white balls remains $5$.Probability of drawing a white ball in the second draw $P(W_2) = \frac{5}{12}$.Since the events are independent,the probability that both balls drawn are white is $P(W_1 \cap W_2) = P(W_1) 	imes P(W_2) = \frac{5}{12} 	imes \frac{5}{12} = \frac{25}{144}$.

$A$ bag contains $7$ black and $5$ white balls. $A$ ball is drawn out and replaced in the bag. Then a ball is drawn again. What is the probability that both the balls drawn were white?

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