A bag contains balls of two colours,3 black a | vedclass

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(B) To ensure that we have at least two balls of the same colour,we apply the Pigeonhole Principle.If we draw $1$ ball,it can be either black or white

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$3$

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(B) To ensure that we have at least two balls of the same colour,we apply the Pigeonhole Principle.If we draw $1$ ball,it can be either black or white.If we draw $2$ balls,they could be one black and one white (different colours).If we draw $3$ balls,according to the Pigeonhole Principle,since there are only $2$ colours available,at least $2$ balls must be of the same colour.Therefore,the minimum number of balls required is $3$.

$A$ bag contains balls of two colours,$3$ black and $3$ white. What is the minimum number of balls which must be drawn from the bag,without looking,so that among these there are two of the same colour?

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