A balanced die is thrown once. Find the proba | vedclass

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(A) There are six elementary outcomes in the experiment of throwing a balanced die once: $1, 2, 3, 4, 5, 6$.Let event $A$ be: 'The number on the die i

Vedclass · Accepted Answer

$\frac{1}{3}$

Vedclass · Answer

(A) There are six elementary outcomes in the experiment of throwing a balanced die once: $1, 2, 3, 4, 5, 6$.Let event $A$ be: 'The number on the die is greater than $4$.'The outcomes favourable to event $A$ are $5$ and $6$.Hence,the number of outcomes favourable to event $A$ is $2$.$	herefore P(A) = P(	ext{The number on the die is greater than } 4) = \frac{	ext{Number of outcomes favourable to } A}{	ext{Number of all possible outcomes}}$.$P(A) = \frac{2}{6} = \frac{1}{3}$.Thus,the probability of getting a number greater than $4$ is $\frac{1}{3}$.

$A$ balanced die is thrown once. Find the probability of getting a number greater than $4$.

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