A balanced die is thrown once. Find the proba | vedclass

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(D) There are six elementary outcomes in the experiment of throwing a balanced die once: $1, 2, 3, 4, 5, 6$.Let event $A$ be: 'The number on the die i

Vedclass · Accepted Answer

$\frac{1}{2}$

Vedclass · Answer

(D) There are six elementary outcomes in the experiment of throwing a balanced die once: $1, 2, 3, 4, 5, 6$.Let event $A$ be: 'The number on the die is a prime number'.The prime numbers among the outcomes are $2, 3, 5$.Thus,the number of outcomes favourable to event $A$ is $3$.The total number of possible outcomes is $6$.Therefore,the probability of event $A$ is $P(A) = \frac{	ext{Number of favourable outcomes}}{	ext{Total number of possible outcomes}} = \frac{3}{6} = \frac{1}{2}$.Thus,the probability of getting a prime number on the die is $\frac{1}{2}$.

$A$ balanced die is thrown once. Find the probability of getting a prime number.

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