A ball is allowed to fall from a height of 10 | vedclass

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(D) Initial potential energy of the ball at height $h = 10\, m$ is $E_i = mgh$.After the impact,$40\%$ of the energy is lost.Therefore,the remaining e

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$6$

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(D) Initial potential energy of the ball at height $h = 10\, m$ is $E_i = mgh$.After the impact,$40\%$ of the energy is lost.Therefore,the remaining energy $E_f$ is $60\%$ of the initial energy.$E_f = 0.60 	imes E_i$.Since the ball rises to a new height $h'$,its final potential energy is $E_f = mgh'$.Equating the energies: $mgh' = 0.60 	imes mgh$.$h' = 0.60 	imes h$.Substituting $h = 10\, m$:$h' = 0.60 	imes 10 = 6\, m$.Thus,the ball will rise to a height of $6\, m$.

List-$I$	List-$II$
$1$. Nitrogen molecules	$(A)$ Continuous spectrum
$2$. Incandescent solids	$(B)$ Absorption spectrum
$3$. Fraunhoffer lines	$(C)$ Band spectrum
$4$. Electric arc between iron rods	$(D)$ Emission spectrum

$A$ ball is allowed to fall from a height of $10\, m$. If there is $40\%$ loss of energy due to impact,then after one impact,the ball will rise to a height of ......... $m$.

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