$A$ balloon is filled with hydrogen at room temperature. It will burst if pressure exceeds $0.2 \ bar$. If at $1 \ bar$ pressure the gas occupies $2.27 \ L$ volume,up to what volume can the balloon be expanded?

(11.35 L) According to Boyle's Law,$p_{1} V_{1} = p_{2} V_{2}$.
Given: $p_{1} = 1 \ bar$,$V_{1} = 2.27 \ L$,and $p_{2} = 0.2 \ bar$.
Substituting the values into the equation:
$V_{2} = \frac{p_{1} V_{1}}{p_{2}}$
$V_{2} = \frac{1 \ bar \times 2.27 \ L}{0.2 \ bar} = 11.35 \ L$.
Since the balloon bursts if the pressure exceeds $0.2 \ bar$,the volume of the balloon can be expanded up to $11.35 \ L$.