$A$ bar magnet of magnetic moment $3.0 \, A-m^2$ is placed in a uniform magnetic induction field of $2 \times 10^{-5} \, T$. If each pole of the magnet experiences a force of $6 \times 10^{-4} \, N$,the length of the magnet is.....$m$

The intensity of magnetization of a bar magnet is $5.0 \times 10^{4} \text{ A m}^{-1}$. The magnetic length and the area of cross-section of the magnet are $12 \text{ cm}$ and $1 \text{ cm}^{2}$ respectively. The magnitude of the magnetic moment of this bar magnet is (in $SI$ unit):

The following figures show the arrangement of bar magnets in different configurations. Each magnet has a magnetic dipole moment $\vec{m}$. Which configuration has the highest net magnetic dipole moment?

$A$ sample of a ferromagnetic iron in the shape of a cube of side $1.0 \mu m$ contains $8.7 \times 10^{28}$ atoms per cubic metre and the magnetic dipole moment of each iron atom is $9.3 \times 10^{-24} A m^2$. Then the maximum possible magnetic dipole moment (in $A m^2$) of the sample is nearly

The resultant magnetic moment of three magnetic dipoles,each of magnetic moment $M$,shown in the arrangement is:

Two identical thin bar magnets,each of length $l$ and pole strength $m$,are placed at a right angle to each other with the north pole of one touching the south pole of the other. The magnetic moment of the system is