(C) The change in length $\Delta L$ is given by the formula: $\Delta L = L_0 \alpha \Delta T$.Here,$L_0 = 10 \, cm$,$\alpha = 11 \times 10^{-6} /^{\ci

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$11 \times 10^{-5} \, cm$ shorter

(C) The change in length $\Delta L$ is given by the formula: $\Delta L = L_0 \alpha \Delta T$.Here,$L_0 = 10 \, cm$,$\alpha = 11 \times 10^{-6} /^{\circ}C$,and $\Delta T = 19^{\circ}C - 20^{\circ}C = -1^{\circ}C$.Substituting the values:$\Delta L = 10 \times (11 \times 10^{-6}) \times (-1) \, cm$.$\Delta L = -110 \times 10^{-6} \, cm = -1.1 \times 10^{-4} \, cm = -11 \times 10^{-5} \, cm$.The negative sign indicates that the bar becomes shorter.Therefore,the bar is $11 \times 10^{-5} \, cm$ shorter.

Class 11 Physics 10-1.Thermometry, Thermal Expansion and Calorimetry Thermal Expansion for Solid

Medium

$A$ bar of iron is $10 \, cm$ at $20^{\circ}C$. At $19^{\circ}C$ it will be ($\alpha$ of iron $= 11 \times 10^{-6}/^{\circ}C$)

A
$11 \times 10^{-6} \, cm$ longer
B
$11 \times 10^{-6} \, cm$ shorter
C
$11 \times 10^{-5} \, cm$ shorter
D
$11 \times 10^{-4} \, cm$ shorter

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10-1.Thermometry, Thermal Expansion and Calorimetry

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Thermal Expansion for Solid

$A$ metal metre scale that is accurate up to $0.5 \ mm$ is made at a temperature of $25^{\circ} C$. The range of temperatures within which it can be used is (Coefficient of linear expansion of the metal $= 10^{-5} /{ }^{\circ} C$)

MediumTS EAMCET 2025

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The ratio among the linear expansion coefficient $(\alpha)$,areal expansion coefficient $(\beta)$,and volume expansion coefficient $(\gamma)$ is:

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Two rods of different metals have coefficients of linear expansion $\alpha_1$ and $\alpha_2$ respectively. Their respective lengths are $L_1$ and $L_2$. At all temperatures,$(L_2 - L_1)$ remains the same. The correct relation is:

MediumMHT CET 2021

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The scale on a steel metre stick is calibrated at $20^{\circ}C$. The error in the reading of $50 \, cm$ at $30^{\circ}C$ is: (take linear expansion coefficient of steel $\alpha = 1.0 \times 10^{-5} / ^{\circ}C$)

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$A$ solid metallic cube having a total surface area of $24 \; m^{2}$ is uniformly heated. If its temperature is increased by $10 \; ^{\circ}C$,calculate the increase in volume of the cube. (Given: $\alpha = 5.0 \times 10^{-4} \; ^{\circ}C^{-1}$)

MediumJEE MAIN 2022

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$A$ bar of iron is $10 \, cm$ at $20^{\circ}C$. At $19^{\circ}C$ it will be ($\alpha$ of iron $= 11 \times 10^{-6}/^{\circ}C$)

Similar Questions

$A$ metal metre scale that is accurate up to $0.5 \ mm$ is made at a temperature of $25^{\circ} C$. The range of temperatures within which it can be used is (Coefficient of linear expansion of the metal $= 10^{-5} /{ }^{\circ} C$)

The ratio among the linear expansion coefficient $(\alpha)$,areal expansion coefficient $(\beta)$,and volume expansion coefficient $(\gamma)$ is:

Two rods of different metals have coefficients of linear expansion $\alpha_1$ and $\alpha_2$ respectively. Their respective lengths are $L_1$ and $L_2$. At all temperatures,$(L_2 - L_1)$ remains the same. The correct relation is:

The scale on a steel metre stick is calibrated at $20^{\circ}C$. The error in the reading of $50 \, cm$ at $30^{\circ}C$ is: (take linear expansion coefficient of steel $\alpha = 1.0 \times 10^{-5} / ^{\circ}C$)

$A$ solid metallic cube having a total surface area of $24 \; m^{2}$ is uniformly heated. If its temperature is increased by $10 \; ^{\circ}C$,calculate the increase in volume of the cube. (Given: $\alpha = 5.0 \times 10^{-4} \; ^{\circ}C^{-1}$)

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