(D) Let the change in temperature be $\Delta T$. The change in length of the first rod is $\Delta L_1 = L_1 \alpha_1 \Delta T$. The change in length o

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(D) Let the change in temperature be $\Delta T$. The change in length of the first rod is $\Delta L_1 = L_1 \alpha_1 \Delta T$. The change in length of the second rod is $\Delta L_2 = L_2 \alpha_2 \Delta T$. Given that the difference $(L_2 - L_1)$ remains constant at all temperatures,the change in length of both rods must be equal. Therefore,$\Delta L_1 = \Delta L_2$. Substituting the expressions,we get $L_1 \alpha_1 \Delta T = L_2 \alpha_2 \Delta T$. Canceling $\Delta T$ from both sides,we obtain the relation $L_1 \alpha_1 = L_2 \alpha_2$.

Class 11 Physics 10-1.Thermometry, Thermal Expansion and Calorimetry Thermal Expansion for Solid

Medium

Two rods of different metals have coefficients of linear expansion $\alpha_1$ and $\alpha_2$ respectively. Their respective lengths are $L_1$ and $L_2$. At all temperatures,$(L_2 - L_1)$ remains the same. The correct relation is:

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A
$L_1 \alpha_1^2 = L_2 \alpha_2^2$
B
$L_1^2 \alpha_1^2 = L_2^2 \alpha_2^2$
C
$L_1 \alpha_2 = L_2 \alpha_1$
D
$L_1 \alpha_1 = L_2 \alpha_2$

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10-1.Thermometry, Thermal Expansion and Calorimetry

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Thermal Expansion for Solid

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Two rods of different metals have coefficients of linear expansion $\alpha_1$ and $\alpha_2$ respectively. Their respective lengths are $L_1$ and $L_2$. At all temperatures,$(L_2 - L_1)$ remains the same. The correct relation is:

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The area of a circular copper coin increases by $0.4 \%$ when its temperature is raised by $100^{\circ} C$. The coefficient of linear expansion of the coin is:

$A$ thin copper wire of length $l$ meters is heated by $10^{\circ}C$,resulting in a $2\%$ increase in its length. If a square copper sheet of side $l$ meters is heated by the same $10^{\circ}C$,what is the percentage change in its area?

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