A beam of protons with speed 4 times 10^{5} | vedclass

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(B) The pitch of a helical path is given by the formula: $P = v \cos 	heta 	imes T = v \cos 	heta 	imes \frac{2 \pi m}{qB}$.Given values:Speed $v

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(B) The pitch of a helical path is given by the formula: $P = v \cos 	heta 	imes T = v \cos 	heta 	imes \frac{2 \pi m}{qB}$.Given values:Speed $v = 4 	imes 10^{5} \ m/s$Magnetic field $B = 0.3 \ T$Angle $	heta = 60^{\circ}$Mass $m = 1.67 	imes 10^{-27} \ kg$Charge $q = 1.6 	imes 10^{-19} \ C$Substituting the values:$P = \frac{2 	imes 3.14 	imes 1.67 	imes 10^{-27} 	imes 4 	imes 10^{5} 	imes \cos 60^{\circ}}{1.6 	imes 10^{-19} 	imes 0.3}$Since $\cos 60^{\circ} = 0.5$:$P = \frac{2 	imes 3.14 	imes 1.67 	imes 10^{-27} 	imes 4 	imes 10^{5} 	imes 0.5}{1.6 	imes 10^{-19} 	imes 0.3}$$P = \frac{10.4872 	imes 10^{-22}}{0.48 	imes 10^{-19}}$$P \approx 0.0437 \ m \approx 4.37 \ cm$.The closest option is $4 \ cm$.

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