A bird flies for 4 , s with a velocity of |t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The velocity of the bird is given by $v(t) = |t - 2| \, m/s$.To find the distance covered in $4 \, s$,we integrate the speed with respect to time

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(B) The velocity of the bird is given by $v(t) = |t - 2| \, m/s$.To find the distance covered in $4 \, s$,we integrate the speed with respect to time from $t = 0$ to $t = 4 \, s$:$S = \int_{0}^{4} |t - 2| \, dt$We can split the integral at $t = 2$ because the expression inside the absolute value changes sign:$S = \int_{0}^{2} -(t - 2) \, dt + \int_{2}^{4} (t - 2) \, dt$$S = \int_{0}^{2} (2 - t) \, dt + \int_{2}^{4} (t - 2) \, dt$$S = [2t - \frac{t^2}{2}]_{0}^{2} + [\frac{t^2}{2} - 2t]_{2}^{4}$$S = (4 - 2) - (0) + [(8 - 8) - (2 - 4)]$$S = 2 + [0 - (-2)] = 2 + 2 = 4 \, m$.Alternatively,the distance is the area under the velocity-time graph,which consists of two right-angled triangles,each with base $2 \, s$ and height $2 \, m/s$.$S = 2 	imes (\frac{1}{2} 	imes 2 	imes 2) = 4 \, m$.

$A$ bird flies for $4 \, s$ with a velocity of $|t - 2| \, m/s$ in a straight line,where $t$ is time in seconds. It covers a distance of ......... $m$.

Similar Questions

The position-time graph of a particle moving along a straight line is shown,which is in the form of a semicircle starting from $t=2 \, s$ to $t=8 \, s$. Select the correct statement.

For the velocity-time graph shown in the figure,the distance covered by the body in the last two seconds of its motion is $S_1$. What is the ratio of $S_1$ to the total distance covered by it?

The position of a particle moving along the $x$-axis is given by $x = 10t - 2t^2$. Then the time $(t)$ at which it will momentarily come to rest is .......... $s$.

The velocity-time and acceleration-time graphs of a particle are given. Its position-time graph may be given as:

The position $x$ of a particle with respect to time $t$ along the $x$-axis is given by $x = 9t^2 - t^3$,where $x$ is in metres and $t$ is in seconds. What will be the position of this particle when it achieves maximum speed along the $x$-direction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module