A block of ice with mass m falls into a lake. | vedclass

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(A) Let the block of ice fall from a height $h$.When the block of ice falls into the lake,its gravitational potential energy is converted into heat en

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$\frac{L}{5g}$

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(A) Let the block of ice fall from a height $h$.When the block of ice falls into the lake,its gravitational potential energy is converted into heat energy upon impact.This heat energy is responsible for melting a portion of the ice.The potential energy lost by the block is $PE = mgh$.The heat required to melt a mass $m/5$ of ice is $Q = (m/5)L$.Equating the potential energy to the heat energy,we get:$mgh = \frac{m}{5}L$Canceling $m$ from both sides,we have:$gh = \frac{L}{5}$Solving for $h$,we get:$h = \frac{L}{5g}$

$A$ block of ice with mass $m$ falls into a lake. After impact,a mass of ice $m/5$ melts. Both the block of ice and the lake have a temperature of $0^{\circ}C$. If $L$ represents the latent heat of fusion,the minimum distance the ice fell before striking the surface is

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