$A$ block of mass $M$ slides down a rough inclined plane with constant velocity. The angle made by the inclined plane with the horizontal is $\theta$. The magnitude of the contact force will be:

  • A
    $Mg$
  • B
    $Mg \cos \theta$
  • C
    $\sqrt{Mg \sin \theta + Mg \cos \theta}$
  • D
    $Mg \sin \theta \sqrt{1 + \mu}$

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