A body of mass 1, kg lies on a smooth incline | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To find the normal reaction $N$,we resolve the forces perpendicular to the inclined plane.The forces acting on the body are:$1$. The weight of the

Vedclass · Accepted Answer

$10 \sqrt{2}\, N$

Vedclass · Answer

(A) To find the normal reaction $N$,we resolve the forces perpendicular to the inclined plane.The forces acting on the body are:$1$. The weight of the body $mg$ acting vertically downwards. Its component perpendicular to the inclined plane is $mg \cos 45^{\circ}$.$2$. The horizontal force $F = 10\, N$. Its component perpendicular to the inclined plane is $F \sin 45^{\circ}$.Since the body is in equilibrium in the direction perpendicular to the plane,the normal reaction $N$ must balance these components:$N = mg \cos 45^{\circ} + F \sin 45^{\circ}$Given $m = 1\, kg$,$g = 10\, m/s^2$,$F = 10\, N$,and $	heta = 45^{\circ}$:$N = (1)(10) \cos 45^{\circ} + 10 \sin 45^{\circ}$$N = 10 \left( \frac{1}{\sqrt{2}} ight) + 10 \left( \frac{1}{\sqrt{2}} ight)$$N = \frac{10}{\sqrt{2}} + \frac{10}{\sqrt{2}} = \frac{20}{\sqrt{2}} = 10 \sqrt{2}\, N$.

$A$ body of mass $1\, kg$ lies on a smooth inclined plane. The body is subjected to a horizontal force $F = 10\, N$ as shown in the figure. The magnitude of the net normal reaction on the body is:

Similar Questions

Two masses $M_1$ and $M_2$ are attached to the ends of a light string which passes over a massless pulley attached to the top of a double inclined smooth plane of angles of inclination $\alpha$ and $\beta$. The tension in the string is:

$A$ body of mass $5\,kg$ is suspended by a spring balance on an inclined plane as shown in the figure. The spring balance measures ............ $N$.

The horizontal acceleration that should be given to a smooth inclined plane of angle $\sin^{-1} (1/l)$ to keep an object stationary on the plane relative to the inclined plane is

Two masses of $8\,kg$ and $4\,kg$ are connected by a string as shown in the figure over a frictionless pulley. The acceleration of the system is ............ $m/s^2$.

$A$ solid sphere,a hollow sphere,and a ring are released from the top of an inclined plane (frictionless) so that they slide down the plane. Then,the maximum acceleration down the plane is for (no rolling):

Vedclass Test Series

Exam Paper Generator

Online Exam Module