$A$ body of mass $m$ is executing $SHM$ with amplitude $a$. When its displacement $x = 1$ unit,the force is $b$. What will be its maximum kinetic energy?

$A$ particle is executing linear $S.H.M.$ starting from the mean position. The ratio of the kinetic energy to the potential energy of the particle at a point of half the amplitude is (in $: 1$)

If a particle repeats its motion after a fixed time interval of $8 \,s$,then after how much time will its maximum value of $PE$ be attained after attaining its minimum value?

The average kinetic energy in one time period of a $SHM$ is :-

$A$ particle starts oscillating simple harmonically from its equilibrium position with time period $T$. At time $t = \frac{T}{12}$,the ratio of its kinetic energy to potential energy is $\left[\sin \frac{\pi}{3} = \cos \frac{\pi}{6} = \frac{\sqrt{3}}{2}, \sin \frac{\pi}{6} = \cos \frac{\pi}{3} = \frac{1}{2}\right]$.

When a particle executing $SHM$ oscillates with a frequency $v$, then the kinetic energy of the particle