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(A) The frequency of the body is given as $f = 140 	ext{ rev/s}$.The relationship between angular speed $\omega$ and frequency $f$ is given by the fo

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$880$

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(A) The frequency of the body is given as $f = 140 	ext{ rev/s}$.The relationship between angular speed $\omega$ and frequency $f$ is given by the formula:$\omega = 2 \pi f$Substituting the given value of $f$:$\omega = 2 	imes \pi 	imes 140$$\omega = 280 \pi 	ext{ rad/s}$Using $\pi \approx 3.14159$:$\omega = 280 	imes 3.14159 \approx 879.64 	ext{ rad/s}$Rounding to the nearest integer,we get:$\omega \approx 880 	ext{ rad/s}$.Therefore,the correct option is $A$.

$A$ body performing uniform circular motion completes $140$ revolutions in a second. Its angular speed is .......... $rad/s$.

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