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(C) Given that the body starts from rest,the initial velocity components are $u_x = 0$ and $u_y = 0$.The acceleration components are $a_x = 6 \; m/s^2

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$80$

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(C) Given that the body starts from rest,the initial velocity components are $u_x = 0$ and $u_y = 0$.The acceleration components are $a_x = 6 \; m/s^2$ and $a_y = 8 \; m/s^2$.The time elapsed is $t = 4 \; s$.Using the kinematic equation $s = ut + \frac{1}{2}at^2$ for both axes:For the $x$-axis: $x = 0(4) + \frac{1}{2} 	imes 6 	imes (4)^2 = 3 	imes 16 = 48 \; m$.For the $y$-axis: $y = 0(4) + \frac{1}{2} 	imes 8 	imes (4)^2 = 4 	imes 16 = 64 \; m$.The distance from the origin is given by $d = \sqrt{x^2 + y^2}$.$d = \sqrt{(48)^2 + (64)^2} = \sqrt{2304 + 4096} = \sqrt{6400} = 80 \; m$.

$A$ body starts from rest from the origin with an acceleration of $6 \; m/s^2$ along the $x$-axis and $8 \; m/s^2$ along the $y$-axis. Its distance from the origin after $4 \; s$ will be (in $; m$)

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