(D) Step $1$: Apply the law of conservation of linear momentum during the collision.$P_i = P_f$$(0.1)(400) = (0.1 + 3.9)v$$40 = 4v$$v = 10\,m/s$Step $

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(D) Step $1$: Apply the law of conservation of linear momentum during the collision.$P_i = P_f$$(0.1)(400) = (0.1 + 3.9)v$$40 = 4v$$v = 10\,m/s$Step $2$: Analyze the motion of the block-bullet system on the rough surface.The frictional force $f = \mu N = \mu (M+m)g$.The retardation $a = \frac{f}{M+m} = \mu g$.Step $3$: Use the equation of motion to find the coefficient of friction $\mu$.$v_f^2 = v_i^2 + 2as$$0 = (10)^2 - 2(\mu g)(20)$$0 = 100 - 40 \mu (10)$$400 \mu = 100$$\mu = \frac{100}{400} = 0.25$

Class 11 Physics Newton's Laws of Motion and Friction Mix Examples-Newton's Laws of Motion and Friction

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$A$ bullet of mass $0.1\,kg$ moving horizontally with speed $400\,m/s$ hits a wooden block of mass $3.9\,kg$ kept on a horizontal rough surface. The bullet gets embedded into the block and moves $20\,m$ before coming to rest. The coefficient of friction between the block and the surface is $........$ (Given $g=10\,m/s^2$)

JEE MAIN 2023 All JEE MAIN

A
$0.50$
B
$0.90$
C
$0.65$
D
$0.25$

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Class 11

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Newton's Laws of Motion and Friction

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Mix Examples-Newton's Laws of Motion and Friction

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In the shown arrangement,if $f_A$,$f_B$ and $T$ are the frictional forces on block $A$,block $B$ and the tension in the string respectively,then their values are:

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