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(B) The lowest intensity of the reflected light is observed when it is completely polarised. This occurs at Brewster's angle $(i_p)$,which is given by

Vedclass · Accepted Answer

$3:32 \, PM$

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(B) The lowest intensity of the reflected light is observed when it is completely polarised. This occurs at Brewster's angle $(i_p)$,which is given by the relation:$	an i_p = \mu = 1.33 = \frac{4}{3}$$\Rightarrow i_p = 	an^{-1} \left( \frac{4}{3} ight) = 53^{\circ}$In the given geometry,the sun moves from the horizon ($A$,$6.00 \, AM$) to the position $P$ where the angle of incidence is $53^{\circ}$. The total time from sunrise to sunset is $12$ hours,corresponding to a $180^{\circ}$ change in the sun's position.The time taken for the sun to move from the horizon $(A)$ to the position $P$ (where the angle of incidence is $53^{\circ}$ with the normal) is calculated as:$t = \frac{12 \, h}{180^{\circ}} 	imes (90^{\circ} + 53^{\circ})$$t = \frac{12}{180} 	imes 143^{\circ} = \frac{143}{15} \, h = 9 \, h + \frac{8}{15} \, h = 9 \, h + 32 \, min$Starting from $6.00 \, AM$,the time is $6.00 + 9 \, h \, 32 \, min = 15:32$,which corresponds to $3:32 \, PM$.

Similar Questions

If the polarizing angle for a medium is $60^\circ$,then the critical angle for that medium is . . . . . .

Select the correct statement.

$A$ ray of light is incident on the surface of a glass plate of refractive index $\sqrt{3}$ at the polarising angle. The angle of refraction of the ray is (in $^{\circ}$)

$A$ ray of light is incident at the polarising angle $\theta$ on an air-glass interface. If $\lambda_a$ and $\lambda_g$ are the wavelengths of light in air and glass respectively, then:

When unpolarized light is incident at an angle of $60^{\circ}$ on a transparent medium from air,the reflected ray is completely polarized. The angle of refraction in the medium is (in $^{\circ}$)

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