A capacitor of capacity C has reactance X. If | vedclass

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(D) The capacitive reactance $X$ is given by the formula $X = \frac{1}{2 \pi f C}$,where $f$ is the frequency and $C$ is the capacitance.Given that th

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$X/4$

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(D) The capacitive reactance $X$ is given by the formula $X = \frac{1}{2 \pi f C}$,where $f$ is the frequency and $C$ is the capacitance.Given that the new capacitance $C^{\prime} = 2C$ and the new frequency $f^{\prime} = 2f$.The new reactance $X^{\prime}$ is calculated as:$X^{\prime} = \frac{1}{2 \pi f^{\prime} C^{\prime}} = \frac{1}{2 \pi (2f) (2C)} = \frac{1}{4 (2 \pi f C)}$.Since $X = \frac{1}{2 \pi f C}$,we substitute this into the equation:$X^{\prime} = \frac{X}{4}$.

$A$ capacitor of capacity $C$ has reactance $X$. If capacitance and frequency become double then reactance will be

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