A car is moving along a straight line,say OP | vedclass

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(A) Average velocity is defined as the ratio of total displacement to the total time interval.$	ext{Average velocity} = \frac{	ext{Displacement}}{

Vedclass · Accepted Answer

$20 \; m \; s^{-1}, 20 \; m \; s^{-1}$

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(A) Average velocity is defined as the ratio of total displacement to the total time interval.$	ext{Average velocity} = \frac{	ext{Displacement}}{	ext{Time interval}}$For the motion from $O$ to $P$,the displacement is $360 \; m - 0 \; m = 360 \; m$ and the time taken is $18 \; s$.$\bar{v} = \frac{360 \; m}{18 \; s} = 20 \; m \; s^{-1}$Average speed is defined as the ratio of total path length to the total time interval.$	ext{Average speed} = \frac{	ext{Path length}}{	ext{Time interval}}$For the motion from $O$ to $P$,the path length is $360 \; m$ and the time taken is $18 \; s$.$	ext{Average speed} = \frac{360 \; m}{18 \; s} = 20 \; m \; s^{-1}$

$A$ car is moving along a straight line,say $OP$ in the given figure. It moves from $O$ to $P$ in $18 \; s$ and returns from $P$ to $Q$ in $6.0 \; s$. What are the average velocity and average speed of the car in going from $O$ to $P$?

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