Class 11Physics3-2.Motion in PlaneNon-uniform Circular Motion (Centrifugal/Centripetal and tangential Accelaration)
Easy$A$ car is travelling with linear velocity $v$ on a circular road of radius $r$. If it is increasing its speed at the rate of $a \ m/s^2$,then the resultant acceleration will be
- A$\sqrt {\frac{v^4}{r^2} - a^2}$
- B$\sqrt {\frac{v^4}{r^2} + a^2}$
- C$\sqrt {\frac{v^2}{r^2} - a^2}$
- D$\sqrt {\frac{v^2}{r^2} + a^2}$
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View SolutionFor a particle in circular motion,$a_r = 3 \ m/s^2$ and $a_T = 4 \ m/s^2$. If $\theta$ is the angle between the resultant acceleration $a$ and the radial acceleration $a_r$,then .......
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View Solution$A$ car is moving on a circular path of radius $500 \ m$ with a speed of $30 \ m/s$. If the speed is increasing at a rate of $2 \ m/s^2$,the net acceleration will be ......... $m/s^2$.
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