A car travels half the distance with a consta | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the total distance be $2d$. The car travels the first half distance $d$ with velocity $v_1 = 40 \, km/h$ and the second half distance $d$ with

Vedclass · Accepted Answer

$48$

Vedclass · Answer

(C) Let the total distance be $2d$. The car travels the first half distance $d$ with velocity $v_1 = 40 \, km/h$ and the second half distance $d$ with velocity $v_2 = 60 \, km/h$.Time taken for the first half is $t_1 = \frac{d}{v_1} = \frac{d}{40}$.Time taken for the second half is $t_2 = \frac{d}{v_2} = \frac{d}{60}$.Average velocity $v_{av} = \frac{	ext{Total distance}}{	ext{Total time}} = \frac{2d}{t_1 + t_2} = \frac{2d}{\frac{d}{40} + \frac{d}{60}}$.$v_{av} = \frac{2}{\frac{1}{40} + \frac{1}{60}} = \frac{2}{\frac{3+2}{120}} = \frac{2 	imes 120}{5} = \frac{240}{5} = 48 \, km/h$.

$A$ car travels half the distance with a constant velocity of $40 \, km/h$ and the remaining half with a constant velocity of $60 \, km/h$. The average velocity of the car in $km/h$ is

Similar Questions

$A$ car moves from $X$ to $Y$ with a uniform speed $v_1$ and returns from $Y$ to $X$ with a uniform speed $v_2$. The average speed for this round trip is

Is it possible for a moving object to have a constant velocity and a changing speed?

Explain average velocity and average speed.

$A$ man walks on a straight road from his home to a market $2.5 \,km$ away with a speed of $5 \,km/h$. Finding the market closed,he instantly turns and walks back home with a speed of $7.5 \,km/h$. The average speed of the man over the interval of time $0$ to $40 \,min$ is equal to

$A$ car moving on a straight road covers one-third of the distance with $20 \, km/hr$ and the rest with $60 \, km/hr$. The average speed is .......... $km/hr$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module