A Carnot engine operates between 227^{circ}C | vedclass

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(B) The efficiency $\eta$ of a Carnot engine is given by the formula: $\eta = 1 - \frac{T_2}{T_1}$,where $T_1$ is the temperature of the source and $T

Vedclass · Accepted Answer

$0.4$

Vedclass · Answer

(B) The efficiency $\eta$ of a Carnot engine is given by the formula: $\eta = 1 - \frac{T_2}{T_1}$,where $T_1$ is the temperature of the source and $T_2$ is the temperature of the sink in Kelvin.First,convert the temperatures from Celsius to Kelvin:$T_1 = 227 + 273 = 500 \ K$$T_2 = 27 + 273 = 300 \ K$Now,substitute these values into the efficiency formula:$\eta = 1 - \frac{300}{500}$$\eta = 1 - 0.6 = 0.4$Therefore,the efficiency of the engine is $0.4$.

$A$ Carnot engine operates between $227^{\circ}C$ and $27^{\circ}C$. The efficiency of the engine will be:

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