A carrier wave of peak voltage 14,V is used f | vedclass

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(A) Given: Modulation index $m = 80\% = 0.8$.Carrier wave peak voltage $E_c = 14\,V$.We know that the modulation index $m$ is defined as the ratio of

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$11.2$

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(A) Given: Modulation index $m = 80\% = 0.8$.Carrier wave peak voltage $E_c = 14\,V$.We know that the modulation index $m$ is defined as the ratio of the peak voltage of the modulating signal $(E_m)$ to the peak voltage of the carrier wave $(E_c)$.Formula: $m = \frac{E_m}{E_c}$.Rearranging the formula to find $E_m$: $E_m = m 	imes E_c$.Substituting the values: $E_m = 0.8 	imes 14\,V = 11.2\,V$.Therefore,the peak voltage of the modulating signal is $11.2\,V$.

$A$ carrier wave of peak voltage $14\,V$ is used for transmitting a message signal. The peak voltage of the modulating signal required to achieve a modulation index of $80\%$ will be.......$V$

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