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Question

(A) From the given figure,the amplitude of the modulating signal $A_m$ is the peak value of the square wave,which is $1 	ext{ V}$.The carrier wave is

Vedclass · Accepted Answer

$0.2$

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(A) From the given figure,the amplitude of the modulating signal $A_m$ is the peak value of the square wave,which is $1 	ext{ V}$.The carrier wave is given by $C(t) = 5 \sin(8\pi t) 	ext{ V}$. Comparing this with the standard carrier wave equation $C(t) = A_C \sin(\omega_c t)$,we get the amplitude of the carrier wave $A_C = 5 	ext{ V}$.The modulation index $\mu$ is defined as the ratio of the amplitude of the modulating signal to the amplitude of the carrier wave:$\mu = \frac{A_m}{A_C}$Substituting the values:$\mu = \frac{1}{5} = 0.2$Thus,the modulation index is $0.2$.

$A$ square wave of the modulating signal is shown in the figure. The carrier wave is given by $C(t) = 5 \sin(8\pi t) \text{ V}$. The modulation index is:

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