$A$ certain prism is found to produce a minimum deviation of $38^\circ$. It produces a deviation of $44^\circ$ when the angle of incidence is either $42^\circ$ or $62^\circ$. What is the angle of incidence when it is undergoing minimum deviation (in $^\circ$)?

The refractive index of the material of a glass prism is $\sqrt{3}$. If the angle of minimum deviation is equal to the angle of the prism,then the angle of the prism is:
$\left(\cos 30^{\circ} = \frac{\sqrt{3}}{2} = \sin 60^{\circ}, \sin 30^{\circ} = \frac{1}{2} = \cos 60^{\circ}\right)$ (in $^{\circ}$)

$A$ ray of light is incident at an angle of $60^o$ on one face of a prism of angle $30^o$. The emergent ray of light makes an angle of $30^o$ with the incident ray. The angle made by the emergent ray with the second face of the prism will be....$^o$

Define the angle of minimum deviation.

When white light passes through a glass prism,one gets a spectrum on the other side of the prism. In the emergent beam,the ray which deviates the least is:

$A$ ray of light passes through an equilateral prism such that the angle of incidence is equal to the angle of emergence. If the angle of incidence is $45^o$,the angle of deviation will be.......$^o$.