The refractive index of the material of a glass prism is $\sqrt{3}$. If the angle of minimum deviation is equal to the angle of the prism,then the angle of the prism is:
$\left(\cos 30^{\circ} = \frac{\sqrt{3}}{2} = \sin 60^{\circ}, \sin 30^{\circ} = \frac{1}{2} = \cos 60^{\circ}\right)$ (in $^{\circ}$)

In an experiment for the determination of the refractive index of glass of a prism by an $i - \delta$ plot,it was found that a ray incident at an angle of $35^o$ suffers a deviation of $40^o$ and emerges at an angle of $79^o$. In that case,which of the following is closest to the maximum possible value of the refractive index?

The angle of a prism is $5^o$ and its refractive indices for red and violet colors are $1.5$ and $1.6$ respectively. The angular dispersion produced by the prism is ......$^o$.

$A$ light ray is incident on a prism at an angle of $60^{\circ}$ and the refracting angle of the prism is $30^{\circ}$. The emergent ray makes an angle of $30^{\circ}$ with the incident ray. The refractive index of the prism is ...

$A$ thin prism of angle $15^o$ made of glass of refractive index $\mu_1 = 1.5$ is combined with another prism of glass of refractive index $\mu_2 = 1.75$. The combination of the prisms produces dispersion without deviation. The angle of the second prism should be ......$^o$

$A$ certain prism is found to produce a minimum deviation of $38^{\circ}$. It produces a deviation of $44^{\circ}$ when the angle of incidence is either $42^{\circ}$ or $62^{\circ}$. What is the angle of incidence when it is undergoing minimum deviation (in $^{\circ}$)?