$A$ charge $Q$ is situated at the corner of a cube. The electric flux passing through all the six faces of the cube is:

The electric field in a region is given by $\vec E = \frac{3}{5}E_0\hat i + \frac{4}{5}E_0\hat j$ and $E_0 = 2 \times 10^3 \, N/C$. Then,the flux of this field through a rectangular surface of area $0.2 \, m^2$ parallel to the $y-z$ plane is ...... $\frac{N \cdot m^2}{C}$.

Gauss's law is given by ${\epsilon _0}\oint {\vec E \cdot d\vec s} = q$. If the net charge enclosed by a Gaussian surface is zero,then .......

If charge $q$ is placed on one of the vertex of a cube, then total electric flux passing through the cube is . . . . . . .

The electric field in the region is $\vec{E} = a\hat{i} + b\hat{j}$ where $a$ and $b$ are constants. The net electric flux passing through a square area of side $l$ parallel to the $Y-Z$ plane is

$A$ uniformly charged conducting sphere of diameter $14 \ cm$ has a surface charge density of $40 \ \mu C/m^2$. The total electric flux leaving the surface of the sphere is nearly (Permittivity of free space $\varepsilon_0 = 8.85 \times 10^{-12} \ C^2/N \cdot m^2$)