A charge moving with velocity v in X-directio | vedclass

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Question

(A) The magnetic force on a moving charge is given by the Lorentz force formula: $\overrightarrow{F_m} = q(\overrightarrow{v} 	imes \overrightarrow{B

Vedclass · Accepted Answer

Remain unaffected

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(A) The magnetic force on a moving charge is given by the Lorentz force formula: $\overrightarrow{F_m} = q(\overrightarrow{v} 	imes \overrightarrow{B})$.Here,the velocity vector $\overrightarrow{v}$ is in the $+X$-direction,and the magnetic field $\overrightarrow{B}$ is in the $-X$-direction.The angle $	heta$ between $\overrightarrow{v}$ and $\overrightarrow{B}$ is $180^\circ$.Since the cross product $\overrightarrow{v} 	imes \overrightarrow{B} = vB \sin(180^\circ) = 0$,the magnetic force $\overrightarrow{F_m}$ is zero.Therefore,the charge will continue to move in the $X$-direction with constant velocity and remain unaffected.

$A$ charge moving with velocity $v$ in $X$-direction is subjected to a field of magnetic induction in the negative $X$-direction. As a result,the charge will

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