A charged particle,initially at rest at O,fol | vedclass

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(A) The correct option is $A$.$1$. Since the charged particle is initially at rest,a magnetic field cannot exert any force on it because the magnetic

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electric field of constant magnitude and varying direction

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(A) The correct option is $A$.$1$. Since the charged particle is initially at rest,a magnetic field cannot exert any force on it because the magnetic force is given by $\vec{F}_m = q(\vec{v} 	imes \vec{B})$,which is zero when $\vec{v} = 0$. Therefore,an electric field is required to initiate the motion.$2$. The electric force is given by $\vec{F}_e = q\vec{E}$. This force causes the particle to accelerate in the direction of the electric field.$3$. If the electric field were constant in both magnitude and direction,the particle would move in a straight line. However,the trajectory shown is a curve.$4$. For the particle to follow a curved path starting from rest,the direction of the force (and thus the direction of the electric field) must change continuously as the particle moves. Therefore,the electric field must have a constant magnitude but a varying direction.

$A$ charged particle,initially at rest at $O$,follows the trajectory shown alongside when released. Such a trajectory is possible in the presence of:

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