A charged particle of mass 5 times 10^{-5} k | vedclass

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(B) For the particle to be held stationary,the upward electric force must balance the downward gravitational force.$F_e = F_g$$|q|E = mg$$|q| = \frac{

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$ - 5 	imes 10^{-5} \ \mu C$

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(B) For the particle to be held stationary,the upward electric force must balance the downward gravitational force.$F_e = F_g$$|q|E = mg$$|q| = \frac{mg}{E}$Given: $m = 5 	imes 10^{-5} \ kg$,$g = 10 \ m/s^2$,$E = 10^7 \ N/C$.$|q| = \frac{5 	imes 10^{-5} 	imes 10}{10^7} = 5 	imes 10^{-11} \ C$.Since $1 \ C = 10^6 \ \mu C$,we have $|q| = 5 	imes 10^{-11} 	imes 10^6 \ \mu C = 5 	imes 10^{-5} \ \mu C$.Since the electric field is directed downwards and the gravitational force acts downwards,the electric force must act upwards to balance it. For a downward electric field,a negative charge experiences an upward force. Therefore,the charge is $-5 	imes 10^{-5} \ \mu C$.

$A$ charged particle of mass $5 \times 10^{-5} \ kg$ is held stationary in space by placing it in an electric field of strength $10^7 \ N C^{-1}$ directed vertically downwards. The charge on the particle is

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