$A$ chord of a circle of radius $20\, cm$ subtends an angle of $90^{\circ}$ at the centre. Find the area of the corresponding major segment of the circle. (Use $\pi=3.14$) (in $cm^2$)

The diameter of a circle with area $154\,cm^{2}$ is $\ldots \ldots \ldots . cm$.

In a circle with radius $14 \, cm$,$\overline{OA}$ and $\overline{OB}$ are radii perpendicular to each other. Then,the area of the minor sector corresponding to $\angle AOB$ is $\ldots \ldots \ldots \, cm^2$.

As shown in the adjoining diagram,the length of the side of the square plot $ABCD$ is $50 \, m$. At each vertex of the plot,a flower bed in the shape of a sector with radius $10 \, m$ is prepared. Find the area of the plot excluding the flower beds. $(\pi = 3.14)$ (in $m^2$)

The ratio of the areas of two circles is $25: 36$. Then,the ratio of their circumferences is:

If the radius of a circle is increased by $10 \%,$ then the corresponding area of the new circle will be $\ldots \ldots \ldots . . .$