A circular coil of diameter 7,cm has 24 turns | vedclass

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(A) The magnetic moment $M$ of a current-carrying coil is given by the formula $M = NiA$,where $N$ is the number of turns,$i$ is the current,and $A$ i

Vedclass · Accepted Answer

$6.9 	imes 10^{-2}\,A\cdot m^2$

Vedclass · Answer

(A) The magnetic moment $M$ of a current-carrying coil is given by the formula $M = NiA$,where $N$ is the number of turns,$i$ is the current,and $A$ is the area of the coil.Given:Number of turns $N = 24$Current $i = 0.75\,A$Diameter $d = 7\,cm = 7 	imes 10^{-2}\,m$Radius $r = d/2 = 3.5 	imes 10^{-2}\,m$Area $A = \pi r^2 = 3.14 	imes (3.5 	imes 10^{-2})^2\,m^2$Substituting the values:$M = 24 	imes 0.75 	imes 3.14 	imes (3.5 	imes 10^{-2})^2$$M = 18 	imes 3.14 	imes 12.25 	imes 10^{-4}$$M = 692.37 	imes 10^{-4} \approx 6.9 	imes 10^{-2}\,A\cdot m^2$

$A$ circular coil of diameter $7\,cm$ has $24$ turns of wire carrying a current of $0.75\,A$. The magnetic moment of the coil is

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