A charged particle (charge q) is moving in a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The magnetic moment $\mu$ of a current loop is given by $\mu = I A$. Here,the current $I$ produced by the revolving charge $q$ is $I = \frac{q}{T}

Vedclass · Accepted Answer

$\frac{qvR}{2}$

Vedclass · Answer

(D) The magnetic moment $\mu$ of a current loop is given by $\mu = I A$. Here,the current $I$ produced by the revolving charge $q$ is $I = \frac{q}{T}$,where $T$ is the time period of revolution. The time period $T$ for a particle moving in a circle of radius $R$ with speed $v$ is $T = \frac{2 \pi R}{v}$. Substituting $T$ into the expression for $I$,we get $I = \frac{q}{2 \pi R / v} = \frac{qv}{2 \pi R}$. The area $A$ of the circular path is $A = \pi R^2$. Therefore,the magnetic moment is $\mu = I A = \left( \frac{qv}{2 \pi R} \right) (\pi R^2) = \frac{qvR}{2}$.

$A$ charged particle (charge $q$) is moving in a circle of radius $R$ with uniform speed $v.$ The associated magnetic moment $\mu$ is given by

Similar Questions

The magnetic moment of a circular coil carrying current is

An electron moves in a circular orbit with a uniform speed $v$. It produces a magnetic field $B$ at the centre of the circle. The radius of the circle is proportional to

$A$ circular coil of radius $10 \text{ cm}$ and $100$ turns carries a current of $1 \text{ A}$. What is the magnetic moment of the coil?

The ratio of the magnetic field at the centre of a current-carrying circular loop to its magnetic moment is '$x$'. When both the current and the radius are tripled, the new ratio will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module