The magnetic moment of a circular coil carryi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The magnetic moment $M$ of a current-carrying coil is given by $M = NiA$,where $N$ is the number of turns,$i$ is the current,and $A$ is the area o

Vedclass · Accepted Answer

Directly proportional to the square of the length of the wire in the coil

Vedclass · Answer

(C) The magnetic moment $M$ of a current-carrying coil is given by $M = NiA$,where $N$ is the number of turns,$i$ is the current,and $A$ is the area of the coil.For a circular coil of radius $r$,the area $A = \pi r^2$.The length of the wire $l$ used to make $N$ turns is $l = N(2\pi r)$,which implies $r = \frac{l}{2\pi N}$.Substituting $A$ in the formula for $M$: $M = Ni(\pi r^2) = Ni\pi (\frac{l}{2\pi N})^2 = Ni\pi \frac{l^2}{4\pi^2 N^2} = \frac{il^2}{4\pi N}$.Assuming the number of turns $N$ is constant,we find that $M \propto l^2$.Therefore,the magnetic moment is directly proportional to the square of the length of the wire.

The magnetic moment of a circular coil carrying current is

Similar Questions

Write the unit and formula of the magnetic dipole moment due to a current-carrying loop.

$A$ circular loop has a radius of $5\, cm$ and it is carrying a current of $0.1\, A$. Its magnetic moment is

Two thick wires and two thin wires,all of the same material and same length,form a square in three different ways $P, Q,$ and $R$ as shown in the figure with the current connection indicated. The magnetic field at the centre of the square is zero in cases:

The relation between magnetic moment $(M)$ of a current-carrying circular coil and the length $(L)$ of the wire used is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module