$A$ circular loop has a radius of $5\, cm$ and it is carrying a current of $0.1\, A$. Its magnetic moment is
- A$1.32 \times 10^{-4}\, A\cdot m^2$
- B$2.62 \times 10^{-4}\, A\cdot m^2$
- C$5.25 \times 10^{-4}\, A\cdot m^2$
- D$7.85 \times 10^{-4}\, A\cdot m^2$
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View SolutionThe ratio of the magnetic field and the magnetic moment at the centre of a current-carrying circular loop is $x$. When both the current and the radius are doubled, the ratio will be:
MediumWBJEE 2010
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