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(C) For a closed pipe of length $l_1$,the fundamental frequency is $f_{c1} = \frac{v}{4l_1}$. The first overtone is the third harmonic,$f_{c,over1} =

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$3:4$

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(C) For a closed pipe of length $l_1$,the fundamental frequency is $f_{c1} = \frac{v}{4l_1}$. The first overtone is the third harmonic,$f_{c,over1} = 3 	imes \frac{v}{4l_1} = \frac{3v}{4l_1}$.For an open pipe of length $l_2$,the fundamental frequency is $f_{o1} = \frac{v}{2l_2}$. The first overtone is the second harmonic,$f_{o,over1} = 2 	imes \frac{v}{2l_2} = \frac{v}{l_2}$.Given that the first overtones are identical in frequency:$\frac{3v}{4l_1} = \frac{v}{l_2}$$\frac{3}{4l_1} = \frac{1}{l_2}$$\frac{l_1}{l_2} = \frac{3}{4}$Therefore,the ratio of their lengths is $3:4$.

$A$ closed pipe and an open pipe have their first overtones identical in frequency. Their lengths are in the ratio:

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