$A$ common transistor radio set requires $12\,V$ $(D.C.)$ for its operation. The $D.C.$ source is constructed by using a transformer and a rectifier circuit,which are operated at $220\,V$ $(A.C.)$ on standard domestic $A.C.$ supply. If the number of turns in the secondary coil is $24$,then the number of turns in the primary coil is:
- A$220$
- B$110$
- C$440$
- D$880$
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An ideal transformer converts $220 \ V$ $AC$ to $3.3 \ kV$ $AC$ to transmit a power of $4.4 \ kW$. If the primary coil has $600$ turns,then the alternating current in the secondary coil is:
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Easy
View Solution$A$ transformer consists of $500$ turns in the primary coil and $10$ turns in the secondary coil with a load of $10\, \Omega$. Find the current in the primary coil when the voltage across the secondary coil is $50\, V$. (in $A$)
MediumAIIMS 2019
View SolutionIf a transformer of an audio amplifier has an output impedance of $8000 \ \Omega$ and the speaker has an input impedance of $8 \ \Omega$,what should be the ratio of the primary to secondary turns of this transformer connected between the amplifier output and the loudspeaker?
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