An ideal transformer converts $220 \ V$ $AC$ to $3.3 \ kV$ $AC$ to transmit a power of $4.4 \ kW$. If the primary coil has $600$ turns,then the alternating current in the secondary coil is:
- A$\frac{5}{3} \ A$
- B$\frac{1}{4} \ A$
- C$\frac{4}{3} \ A$
- D$\frac{2}{3} \ A$
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