A compound with molecular mass 180 is acylate | vedclass

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(B) During acetylation,one $H$ atom (atomic mass $1 \, u$) of an $-NH_2$ group is replaced by an acetyl group $(CH_3CO-)$ with a molecular mass of $43

Vedclass · Accepted Answer

$5$

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(B) During acetylation,one $H$ atom (atomic mass $1 \, u$) of an $-NH_2$ group is replaced by an acetyl group $(CH_3CO-)$ with a molecular mass of $43 \, u$.The reaction is: $-NH_2 + CH_3COCl \longrightarrow -NHCOCH_3 + HCl$.This indicates that the acylation of each $-NH_2$ group increases the molecular mass of the compound by $(43 - 1) = 42 \, u$.Given that the initial molecular mass is $180 \, u$ and the final molecular mass is $390 \, u$,the total increase in mass is $390 - 180 = 210 \, u$.Therefore,the number of $-NH_2$ groups present is $\frac{210}{42} = 5$.

$A$ compound with molecular mass $180$ is acylated with $CH_3COCl$ to get a compound with molecular mass $390$. The number of amino groups present per molecule of the former compound is:

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