$A$ concave mirror and a converging lens (glass with $\mu = 1.5$) both have a focal length of $3 \, cm$ when in air. When they are in water $\left( \mu = \frac{4}{3} \right)$,what are their new focal lengths?

  • A
    $f_{Lens} = 12 \, cm, f_{Mirror} = 3 \, cm$
  • B
    $f_{Lens} = 3 \, cm, f_{Mirror} = 12 \, cm$
  • C
    $f_{Lens} = 3 \, cm, f_{Mirror} = 3 \, cm$
  • D
    $f_{Lens} = 12 \, cm, f_{Mirror} = 12 \, cm$

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$A$ glass beaker has a solid,plano-convex base of refractive index $1.60$,as shown in the figure. The radius of curvature of the convex surface $(SPU)$ is $9 \ cm$,while the planar surface $(STU)$ acts as a mirror. This beaker is filled with a liquid of refractive index $n$ up to the level $QPR$. If the image of a point object $O$ at a height of $h$ ($OT$ in the figure) is formed onto itself,then which of the following option$(s)$ is (are) correct?
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