A cone of height 12 , cm has a volume 616 , c | vedclass

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Question

(C) The volume $V$ of a cone is given by the formula $V = \frac{1}{3} \pi r^2 h$,where $r$ is the radius and $h$ is the height.Given: $V = 616 \, cm^3

Vedclass · Accepted Answer

$14$

Vedclass · Answer

(C) The volume $V$ of a cone is given by the formula $V = \frac{1}{3} \pi r^2 h$,where $r$ is the radius and $h$ is the height.Given: $V = 616 \, cm^3$ and $h = 12 \, cm$.Using $\pi \approx \frac{22}{7}$,we have:$616 = \frac{1}{3} 	imes \frac{22}{7} 	imes r^2 	imes 12$$616 = 4 	imes \frac{22}{7} 	imes r^2$$616 = \frac{88}{7} 	imes r^2$$r^2 = \frac{616 	imes 7}{88}$$r^2 = 7 	imes 7 = 49$$r = 7 \, cm$.The diameter $d$ is $2r = 2 	imes 7 = 14 \, cm$.

$A$ cone of height $12 \, cm$ has a volume $616 \, cm^3$. Then its diameter is $\ldots \ldots \ldots \, cm$.

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