$A$ conical tent with radius $7\, m$ and slant height $12\, m$ is to be made. How many metres of $2\, m$ wide tarpaulin will be required? If the price of tarpaulin is ₹ $48$ per meter,find the cost of the tarpaulin.

(A) For a given cone:
Radius $(r) = 7\, m$ and slant height $(l) = 12\, m$.
Area of tarpaulin used in the tent = Curved surface area of the cone.
Curved surface area $= \pi r l = \frac{22}{7} \times 7 \times 12 = 264\, m^2$.
Since the area of the tarpaulin is $l \times b$,where $b = 2\, m$:
$264 = l \times 2 \implies l = \frac{264}{2} = 132\, m$.
Thus,$132\, m$ of tarpaulin is required.
Cost of $1\, m$ tarpaulin = ₹ $48$.
Total cost = $132 \times 48 = ₹ 6336$.