A contract is to be completed in 92 days and | vedclass

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(A) Remaining work $= (1 - \frac{4}{7}) = \frac{3}{7}$.Remaining period $= (92 - 66) = 26$ days.Let the number of additional men be $x$.Using the form

Vedclass · Accepted Answer

$162$

Vedclass · Answer

(A) Remaining work $= (1 - \frac{4}{7}) = \frac{3}{7}$.Remaining period $= (92 - 66) = 26$ days.Let the number of additional men be $x$.Using the formula $\frac{M_1 D_1 H_1}{W_1} = \frac{M_2 D_2 H_2}{W_2}$:$M_1 = 234, D_1 = 66, H_1 = 16, W_1 = \frac{4}{7}$.$M_2 = (234 + x), D_2 = 26, H_2 = 18, W_2 = \frac{3}{7}$.Substituting the values:$\frac{234 	imes 66 	imes 16}{4/7} = \frac{(234 + x) 	imes 26 	imes 18}{3/7}$.$234 	imes 66 	imes 16 	imes 3 = (234 + x) 	imes 26 	imes 18 	imes 4$.$234 + x = \frac{234 	imes 66 	imes 16 	imes 3}{26 	imes 18 	imes 4}$.$234 + x = 9 	imes 11 	imes 4 = 396$.$x = 396 - 234 = 162$.Therefore,$162$ additional men are required.

$A$ contract is to be completed in $92$ days and $234$ men were set to work,each working $16$ hours a day. After $66$ days,$\frac{4}{7}$ of the work is completed. How many additional men may be employed,so that the work may be completed in time,each man now working $18$ hours a day?

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